A) 18
B) 15
C) 12
D) 6
Correct Answer: A
Solution :
According to charge balance, number of \[F{{e}^{3+}}\] ions replacing x \[F{{e}^{+2}}\] ions is equal to \[\frac{2x}{3}\] \[\therefore \] Vacancies of cations \[\,\,=x-\frac{2x}{3}=\frac{x}{3}\] But \[\frac{x}{3}=1-0.94\,=0.06\] \[x=0.06\,\times 3=0.18\] or 18% Sol.69 \[C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow[P]{C{{l}_{2}}}C{{H}_{3}}\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}\,-COOH\] \[\xrightarrow{KOH(alc.)}\,C{{H}_{2}}\,=CHCOOH\]
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