A) \[C{{H}_{3}}\underset{OH}{\mathop{\underset{|}{\mathop{CHCOOH}}\,}}\,\]
B) \[C{{H}_{2}}\underset{OH}{\mathop{\underset{|}{\mathop{C{{H}_{2}}COOH}}\,}}\,\]
C) \[C{{H}_{2}}=CHOOH\]
D) \[\underset{OH}{\mathop{\underset{|}{\mathop{C{{H}_{2}}}}\,}}\,\underset{OH}{\mathop{\underset{|}{\mathop{CHCOOH}}\,}}\,\]
Correct Answer: C
Solution :
\[C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow[P]{C{{l}_{2}}}C{{H}_{3}}\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}\,-COOH\] \[\xrightarrow{KOH(alc.)}\,C{{H}_{2}}\,=CHCOOH\]
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