A) \[2.303\times 2cal\]
B) \[\frac{2}{2.303}cal\]
C) \[2cal\]
D) None of these
Correct Answer: C
Solution :
We know, \[\log k=\log A-\frac{{{E}_{a}}}{2.303RT}\] compare this by \[y=mx+C\] \[m=-\,\frac{{{E}_{a}}}{2.303R}\] slope of this Given \[-\frac{{{E}_{a}}}{2.303R}\,=-\frac{1}{2.303}\] \[{{E}_{a}}=R=2\,cal\]You need to login to perform this action.
You will be redirected in
3 sec