A) \[40\sqrt{2}\frac{kg{{m}^{2}}}{\sec }\]
B) \[400\sqrt{2}\frac{kg{{m}^{2}}}{\sec }\]
C) \[800\frac{kg{{m}^{2}}}{\sec }\]
D) None
Correct Answer: B
Solution :
\[R=\frac{{{u}^{2}}\sin 2\theta }{g}=40\] \[{{L}_{0}}=\] line of linear moment. shortest distance \[=(mv\sin \theta )\times R\]You need to login to perform this action.
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