A) \[2.4\pi \times {{10}^{-5}}H\]
B) \[4.8\pi \times {{10}^{-4}}H\]
C) \[4.8\pi \times {{10}^{-5}}H\]
D) \[2.4\pi \times {{10}^{-4}}H\]
Correct Answer: D
Solution :
The mutual inductance is: \[M=\frac{{{\mu }_{0}}\,{{N}_{1}}{{N}_{2}}A}{\ell }\] \[=\,\frac{4\pi \times {{10}^{-7}}\,\times 300\,\times 400\,\times 10\,\times {{10}^{-4}}}{0.2}\] \[=2.4\,\pi \times {{10}^{-4}}H\]You need to login to perform this action.
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