A) \[\lambda '=\lambda /2\]
B) \[\lambda '=2\lambda \]
C) \[\lambda '>\lambda \]
D) \[\frac{\lambda }{2}<\lambda '<\lambda \]
Correct Answer: D
Solution :
\[E=\frac{hc}{\lambda }-\phi \] \[2E=\frac{hc}{\lambda '}-\phi \] \[2\left( \frac{hc}{\lambda }-\phi \right)\,=\frac{hc}{\lambda '}-\phi \] \[2\frac{hc}{\lambda }>\frac{hc}{\lambda '}\] \[\lambda '\,>\frac{\lambda }{2}\] \[\because \] Energy of photoelectron is increased hence \[\lambda \] must be decreased. i.e., \[\lambda '\,<\lambda \]You need to login to perform this action.
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