A) \[\lambda =10cm\]
B) amplitude =0.04 cm
C) velocity v = 5 cm/s
D) frequency = f =20 Hz
Correct Answer: A
Solution :
\[\lambda =\,\frac{2\pi }{k}=\frac{2\pi }{\left( \frac{\pi }{9} \right)}\,=18\] Where \[y=A\sin (\omega t-kx+\phi )\]You need to login to perform this action.
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