A) \[\lambda <-5\]
B) \[\lambda >3\]
C) \[-5>\lambda <-3\]
D) \[0>\lambda <3\]
Correct Answer: B
Solution :
Any normal is \[y=mx-2am-a{{m}^{3}},\] where \[a=\frac{3}{2}\] \[\therefore \,\,(\lambda ,0)\,\,\Rightarrow 0=m\lambda -2am-a{{m}^{3}}\] \[\Rightarrow m=0,{{m}^{2}}=\frac{\lambda }{a}-2>0\] \[\Rightarrow \,\lambda \,>\,2a\,\Rightarrow \,\lambda \,>\,3\]You need to login to perform this action.
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