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JEE Main & Advanced Sample Paper JEE Main Sample Paper-34

  • question_answer
    Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross sectional area \[A=10\text{ }c{{m}^{2}}\] and length = 20 cm. If one of the solenoids has 300 turns and the other 400 turns, their mutual inductance is \[({{\mu }_{0}}=4\pi \times {{10}^{-7}}Tm{{A}^{-1}})\]

    A)  \[2.4\pi \times {{10}^{-5}}H\]   

    B)  \[4.8\pi \times {{10}^{-4}}H\]

    C)   \[4.8\pi \times {{10}^{-5}}H\]  

    D)  \[2.4\pi \times {{10}^{-4}}H\]

    Correct Answer: D

    Solution :

    The mutual inductance is: \[M=\frac{{{\mu }_{0}}\,{{N}_{1}}{{N}_{2}}A}{\ell }\]             \[=\,\frac{4\pi \times {{10}^{-7}}\,\times 300\,\times 400\,\times 10\,\times {{10}^{-4}}}{0.2}\]             \[=2.4\,\pi \times {{10}^{-4}}H\]


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