JEE Main & Advanced Sample Paper JEE Main Sample Paper-34

  • question_answer
    In an n - p - n transistor amplifier circuit, when working in common emitter configuration, when the input signal changes by 0.02 V, the base current changes by \[10\mu A\] and the collector current by 1mA. the load in the collector circuit is \[10k\Omega ,\], the power gain is

    A)  \[{{10}^{4}}\]                                   

    B)  \[2\times {{10}^{4}}\]

    C)  \[5\times {{10}^{4}}\]                  

    D)  \[5\times {{10}^{3}}\]

    Correct Answer: C

    Solution :

    \[{{r}_{i}}=\frac{\Delta {{V}_{i}}}{\Delta {{I}_{g}}}\,=\frac{0.02}{10\times {{10}^{-6}}}\,=2\times {{10}^{3}}\Omega \]             Power gain \[={{\left( \frac{\Delta {{I}_{C}}}{\Delta {{I}_{g}}} \right)}^{2}}\,\frac{{{r}_{0}}}{{{r}_{i}}}\]             \[=\left( \frac{{{10}^{3}}}{10\times {{10}^{-6}}} \right)\,\times \frac{10\times {{10}^{3}}}{2\times {{10}^{3}}}\,=5\times {{10}^{4}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner