question_answer

If 1 /2 moles of oxygen combine with aluminum to form \[A{{l}_{2}}{{O}_{3}}\] then weight of Aluminum metal used in the reaction is (Al = 27)-

A)  27 g

B)  18 g

C)  54 g

D)  40.5 g

Correct Answer: B

Solution :

              From mole-mole analysis             (here n= mole)