A) tautology
B) contradiction
C) neither tautology nor contradiction
D) either tautology or contradiction
Correct Answer: C
Solution :
Let \[s=\tilde{\ }\,\,(p\hat{\ }q)\,\,\vee \,\tilde{\ }(q\Leftrightarrow p)\]| P | q | \[\tilde{\ }\,(p\hat{\ }q)\] | \[\tilde{\ }\,(q\Leftrightarrow p)\] | s |
| T | T | F | F | F |
| T | F | T | T | T |
| F | T | T | T | T |
| F | F | T | F | T |
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