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JEE Main & Advanced Sample Paper JEE Main Sample Paper-35

  • question_answer
    Time period (T) and amplitude  are same for two particles which undergo SHM along the same line. At one particular instant, one particle is at phase \[\frac{3\pi }{2}\] and other is at phase zero, while moving in the same direction. Find the time at which they will cross each other.

    A)  \[4T/3\]                              

    B)  \[3T/8\]

    C)  \[3T/4\]                              

    D)  \[3T/7\]

    Correct Answer: B

    Solution :

    At phase \[3\pi /2,\,\,(\omega t+\phi )\,\,=3\pi /2\]             \[{{x}_{1}}=A\,\sin \frac{3\pi }{2}\,=-A\]             \[{{x}_{2}}=0\]             So, at \[t=0,\,\,{{x}_{1}}=-A\,\cos \,\omega t\,\]  and \[{{x}_{2}}=A\sin \omega t\]  \[{{x}_{1}}={{x}_{2}}\]             \[-\cos \omega t=\sin \omega t\]             \[\tan \omega t=-1\]             \[\omega t\,=\frac{3\pi }{4}\]             \[\left( \frac{2\pi }{T} \right)\,t=\frac{3\pi }{4}\]           \[t=3T/8\].


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