A) \[1+\frac{a}{g}\]
B) \[1-\frac{a}{g}\]
C) \[1+\frac{2a}{g}\]
D) \[1-\frac{2a}{g}\]
Correct Answer: C
Solution :
Relative acceleration of M relative to m \[=2a=a(-a)\] In lift frame since, M > m, M is moving downward with acceleration a.You need to login to perform this action.
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