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Correct Answer: A
Solution :
Heat supplied in raising temperature from \[(-{{10}^{o}}C)\] to \[0{}^\circ C\]\[{{Q}_{1}}=m{{s}_{1}}\,(10),\] where \[{{s}_{1}}\] is specific heat of ice when ice starts melting, its temperature during melting remains constant. Heat supplied during melting\[{{Q}_{2}}=mL\]. Heat supplied in raising temperature from \[0{}^\circ C\]to\[100{}^\circ C\], \[{{Q}_{3}}=m{{s}_{w}}(100),\] where \[{{s}_{w}}\] is specific heat of water. The temperature will again remain constant, when water is converted into steam at\[100{}^\circ C\].You need to login to perform this action.
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