A) 2
B) \[-2\]
C) 4
D) \[-4\]
Correct Answer: D
Solution :
Equation of the circle touching the line \[3x+y+2=0\] at (-1, 1) is \[{{(x+1)}^{2}}\,+{{(y-1)}^{2}}\,+\lambda (3x+y+2)=0\]\ It passes through (3, 5) \[\Rightarrow \,16+16+\lambda (\,9+5+2)\,=0\Rightarrow \,\lambda =-2\] \[\therefore \,\,\,\] Equation of circle is \[{{(x-1)}^{2}}\,+{{(y-1)}^{2}}-2(3x+y+2)=0\] \[\Rightarrow \,\,{{x}^{2}}+{{y}^{2}}-4x-4y\,-2=0\]You need to login to perform this action.
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