A) infinite
B) \[{{\log }_{e}}2\]
C) \[{{\log }_{10}}2\]
D) zero
Correct Answer: B
Solution :
For the charging of the capacitor we know that \[q={{q}_{0}}\,(1-{{e}^{{}^{-t}/{}_{Rc}}})\] \[q/C=({{q}_{0}}/C)\,(1-{{e}^{-t/RC}})\] \[V={{V}_{0}}\,(1-{{e}^{-t/RC}})\,\] hence \[0.75\,=1.5\,(1-e\,-t/1)\] and hence \[t={{\log }_{e}}2\]You need to login to perform this action.
You will be redirected in
3 sec