JEE Main & Advanced
Sample Paper
JEE Main Sample Paper-35
question_answer
For the cell, \[Hg\left| H{{g}_{2}}C{{l}_{2}} \right|C{{l}^{-}}(0.1\,M)||\,C{{l}^{-}}(0.01\,M)\]\[\left| C{{l}_{2}},Pt\,{{E}^{o}}_{cell}=1.10\,V \right.\], Hence \[{{E}_{cell}}\] is
A) \[1.1591\] V
B) \[-1.1591\] V
C) \[1.0409\] V
D) \[-1.0409\] V
Correct Answer:
A
Solution :
\[{{E}_{cell}}\] is calculated from nemxt equation.