A) \[-6{{E}_{1}}\]
B) \[-8{{E}_{1}}\]
C) \[-9{{E}_{1}}\]
D) Zero
Correct Answer: C
Solution :
Total exchange energy \[=-\,\left\{ \frac{r!}{2(r-2)!}\,+\frac{s!}{2(s-2)!} \right\}\times {{E}_{1}}\] r= number of \[{{e}^{-}}\] having clockwise spin s = number of \[{{e}^{-}}\] having anticlockwise spin \[r=3,\,s=4\] \[=\left[ \frac{3!}{2\times 1}+\frac{4!}{2\times 2!} \right]\,\,{{E}_{1}}\,=-\left[ 3+\frac{4\times 3}{2} \right]{{E}_{1}}=-9{{E}_{1}}\]You need to login to perform this action.
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