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  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-35

  • question_answer
    Temperatures of source and sink of carnot engine is 400 K and 300 K. Its efficiency is-

    A)  100%                                   

    B)  75%

    C)  33.3%                                  

    D)  25%

    Correct Answer: D

    Solution :

    efficiency=\[1-\frac{{{T}_{1}}}{{{T}_{2}}}=1-300/400\,=1/4\]percentage efficiency = 100/4 = 25 


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