A) 23
B) 25
C) 24
D) 33
Correct Answer: C
Solution :
The configuration of atom of 4th period with maximum unpaired electrons is \[1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{5}}4{{s}^{1}}.\] Hence its atomic number is 24.
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