A) \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}Br\]
B) \[C{{H}_{3}}Br\]
C) \[{{(C{{H}_{3}})}_{2}}CHBr\]
D) \[{{(C{{H}_{3}})}_{3}}CBr\]
Correct Answer: A
Solution :
Because of the formation of the most stable carboniumion, \[{{C}_{6}}{{H}_{5}}-\overset{+}{\mathop{C}}\,{{H}_{2}}\]
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