A) B will give an isomer of A
B) C will give an isomer of A
C) Neither of them will give isomer of A
D) Both B and C will give isomer of A
Correct Answer: B
Solution :
Entiomers of \[{{C}_{4}}{{H}_{10}}O\] are \[\left. {{H}_{3}}C{{H}_{2}}C-\underset{H}{\mathop{\underset{|}{\mathop{\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-C{{H}_{3}} \right|{{H}_{3}}C-\underset{H}{\mathop{\underset{|}{\mathop{\overset{HO}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-C{{H}_{2}}C{{H}_{3}}\] \[C{{H}_{3}}C{{H}_{{{2}^{-}}}}\underset{A}{\mathop{\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,H-C{{H}_{3}}\xrightarrow{{{H}_{2}}S{{O}_{4}}}\]\[\underset{Major\,(B)}{\mathop{C{{H}_{3}}CH=CH+C{{H}_{3}}}}\,+C{{H}_{2}}=\underset{Minor\,(C)}{\mathop{CHC{{H}_{2}}C{{H}_{3}}}}\,\]
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