A) \[3\le n(A\cup B)\le 6\]
B) \[3\le n(A\cup B)\le 9\]
C) \[6\le n(A\cup B)\le 9\]
D) \[0\le n(A\cup B)\le 9\]
Correct Answer: C
Solution :
We have\[\min n(A\cup B)=\max \{n(A),\,\,n(B)\}=\max \{3,\,\,6\}=6\]\[\text{Max}\,\,n(A\cup B)=n(A)+n(B)=9\] \[\therefore \]\[6\le n(A\cup B)\le 9\]You need to login to perform this action.
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