A) \[2\]
B) \[1\]
C) \[0\]
D) infinite
Correct Answer: A
Solution :
\[f\{f[f(x)]\}=f\left[ f\left( \frac{1}{1-x} \right) \right]=f\left( \frac{1}{1-\frac{1}{1-x}} \right)=f\left( \frac{x-1}{x} \right)\]\[\therefore \]\[f(x)\]is not defined for\[x=1;\,\,f\left( \frac{1}{1-x} \right)\]is not defined for\[x=0\]. \[\therefore \]\[f\{f[f(x)]\}\]is discontinuous at \[x=0\] and 1 \[i.e.,\]there are two points of discontinuity.You need to login to perform this action.
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