question_answer

A \[1.0\text{ }M\] solution with respect to each of the metal halides \[A{{X}_{3}},B{{X}_{2}},C{{X}_{3}}\] and \[D{{X}_{2}}\] is electro lysed using platinum electrodes. If \[{{E}^{o}}_{{{A}^{3+}}/A}=1.50V,\,{{E}^{o}}_{{{B}^{2+}}/B}=0.3V,\,{{E}^{o}}_{{{C}^{3+}}/C}=-0.74V,{{E}^{o}}_{{{D}^{2+}}/D}=-23.7V.\] The correct sequence in which the various metals are deposited at the cathode is

A)  A, B, C, D                   

B)  A, B, C

C)  D, C, B, A                   

D)  C, B, A