A) \[52,48\]
B) \[42,25\]
C) \[25,42\]
D) None
Correct Answer: C
Solution :
Let atomic masses of A and B be a and b amu respectively \[\therefore \]Molar mass of \[A{{B}_{2}}=(a+2b)g\,mo{{l}^{-1}}\]and Molar mass of \[A{{B}_{4}}=(a+4b)g\,mo{{l}^{-1}}\] For compound \[A{{B}_{2}}\] \[\Delta {{T}_{b}}={{K}_{b}}\times {{W}_{B}}\times 1000/{{W}_{A}}\times {{M}_{B}}\] \[2.3=5.1\times 1\times 1000/20.0\times (a+2b)...I\] For compound \[A{{B}_{4}}\] \[1.3=5.1\times 1\times 1000/20.0\times (a+4b)....II\] Solving (I) and (II), \[a=25.49\] \[b=42.64\]You need to login to perform this action.
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