A) \[3\,\mu C\]
B) \[9\,\mu C\]
C) \[6\,\mu C\]
D) \[12\,\mu C\]
Correct Answer: B
Solution :
As \[{{S}_{2}}\] is open, hence \[{{C}_{1}}\] & \[{{C}_{3}}\] are in series, also \[{{C}_{2}}\] & \[{{C}_{4}}\] are in series combination, \[Q=\frac{3}{4}\times V=\frac{3}{4}\times 12=9\mu C;\]You need to login to perform this action.
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