A) \[a=3,\,\,b=-3\]
B) \[a=9,\,\,b=3\]
C) \[a=0,\,\,b=-6\]
D) \[a=3,\,\,b=9\]
Correct Answer: B
Solution :
Both the curves satisfied by the point\[(1,\,\,{{y}_{1}}).\] So\[,\]\[1+a-1=6+b\Rightarrow a-b=6\] ? (1) Also\[{{\left. \frac{dy}{dx} \right|}_{curve\,\,1}}={{\left. \frac{dy}{dx} \right|}_{curve\,\,2}}\]at\[x=1\] \[{{[3{{x}^{2}}+a]}_{x=1}}={{[12x]}_{x=1}}\Rightarrow a=9\] ... (2) From (1) & (2),\[a=9\]and\[b=3\].You need to login to perform this action.
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