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JEE Main & Advanced Sample Paper JEE Main Sample Paper-37

  • question_answer
    The variation of concentration of A with time in two experiments starting with two different initial concentration of A is given in the following graph. The reaction is represented as \[A(aq)\to B(aq)\]. What is the rate of reaction (M/min) when concentration of A in aqueous solution was \[1.8M\]?

    A) \[0.072M\,{{\min }^{-1}}\]

    B) \[0.036M\,{{\min }^{-1}}\]

    C) \[0.1296M\,{{\min }^{-1}}\]

    D) \[1M\,{{\min }^{-1}}\]

    Correct Answer: A

    Solution :

     Rate law \[r=k{{[A]}^{m}}\] \[{{r}_{1}}=\left( \frac{0.3}{5} \right)M/\min \] min from graph (exp. 1) \[{{r}_{2}}=\left( \frac{0.2}{5} \right)M/\min \] from graph (exp. 2) \[\frac{{{r}_{1}}}{{{r}_{2}}}=\frac{3}{2}={{\left\{ \frac{{{[A]}_{1}}}{{{[A]}_{2}}} \right\}}^{m}}={{\left( \frac{1.5}{1} \right)}^{m}}\Rightarrow m=1\] \[\frac{0.3}{5}=k(1.5)\Rightarrow k=\frac{1}{25}{{\min }^{-1}}\] \[r=k\times [A]\Rightarrow \frac{1}{25}\times 1.8=0.072\,M\,{{\min }^{-1}}\]


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