A) \[{{O}_{2}}\]
B) \[{{N}_{2}}\]
C) \[N{{O}_{2}}\]
D) \[{{N}_{2}}O\]
Correct Answer: D
Solution :
\[N{{H}_{4}}Cl{{O}_{4}}+HN{{O}_{3}}\underset{(X)}{\mathop{(diltute)}}\,\to N{{H}_{4}}N{{O}_{3}}+HCl{{O}_{4}}\]\[\underset{(X)}{\mathop{N{{H}_{4}}N{{O}_{3}}}}\,\xrightarrow{heat}\underset{(Y)}{\mathop{{{N}_{2}}O}}\,+2{{H}_{2}}O\]
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