A) \[600\,K\]
B) \[300\,K\]
C) \[1200\,K\]
D) \[1000\,K\]
Correct Answer: A
Solution :
Mole of X reacted \[=0.75\]mole Heat liberated at constant pressure \[=0.75\times 10\,kJ=7.5kJ\] Mole of X remaining \[=\frac{1}{4}mole\] Mole of Y formed \[=\frac{3}{4}\times \frac{2}{3}=\frac{1}{2}\] \[\left( \frac{1}{4}{{C}_{p.m(X)}}+\frac{1}{2}{{C}_{p.m(Y)}} \right)\,\,(\Delta T)=q=7500\] \[\Delta T=\frac{7500}{\frac{40}{4}+\frac{30}{2}}=300\] Final temperature \[=300+300=600\text{ }K\]You need to login to perform this action.
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