JEE Main & Advanced Sample Paper JEE Main Sample Paper-37

  • question_answer
    DIRECTIONS: Read the following passage and answer the questions that follows:
    A monoatomic ideal gas is filled in a no conducting container. The gas can be compressed by a movable no conducting piston. The gas is compressed slowly to 12.5% of its initial volume.
    The initial adiabatic bulk modulus of the gas is \[{{B}_{i}}\] and the final value of the adiabatic bulk modulus of the gas is \[{{B}_{f}}\].then

    A)  \[32{{B}_{i}}={{B}_{f}}\]            

    B)  \[{{B}_{i}}={{B}_{f}}\]

    C)  \[{{B}_{i}}=32{{B}_{f}}\]            

    D)  \[{{B}_{i}}=4{{B}_{f}}\]

    Correct Answer: A

    Solution :

     Adiabatic bulk modulus \[B=-V\frac{dP}{dV}=\gamma P=\gamma \frac{nRT}{V}\] \[\therefore \] \[\frac{{{B}_{i}}}{{{B}_{r}}}=\frac{{{T}_{0}}}{{{V}_{0}}}\times \frac{V}{T}=\frac{{{T}_{0}}}{{{V}_{0}}}\times \frac{{{V}_{0}}/8}{4{{T}_{0}}}=\frac{1}{32}\]


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