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JEE Main & Advanced Sample Paper JEE Main Sample Paper-37

  • question_answer
    The locus of the centres of the circles which cut the circles \[{{x}^{2}}+{{y}^{2}}+4x-6y+9=0\] and\[{{x}^{2}}+{{y}^{2}}-4x+4y-2=0\] orthogonally is -

    A) \[9x+10y-7=0\]         

    B) \[x-y+2=0\]

    C) \[9x-10y+11=0\]       

    D) \[9x+10y+7=0\]

    Correct Answer: C

    Solution :

     Given circles are\[{{x}^{2}}+{{y}^{2}}+4x-6y+9=0\] and\[{{x}^{2}}+{{y}^{2}}-5x+4y-2=0\] \[\therefore \]locus of centres is \[9x-10y+11=0\]


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