A) \[x+7y=0\]
B) \[x-y=0\]
C) \[x-7y=0\]
D) Both [a] and [b]
Correct Answer: D
Solution :
Centre of the circle is\[\left( \frac{1}{2},\,\,-\frac{3}{2} \right)\]. Its distance from the line\[x+y-1\]is\[\sqrt{2}\]. Let the required line be\[mx-y=0\] \[\therefore \] \[\left| \frac{\frac{m}{2}+\frac{3}{2}}{\sqrt{{{m}^{2}}+1}} \right|=\sqrt{2}\Rightarrow m=1,\,\,-17\] \[\therefore \] The lines are\[x-y=0,\,\,x+7y=0\]You need to login to perform this action.
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