A) \[0.99%\]
B) \[25%\]
C) \[50%\]
D) \[75%\]
Correct Answer: C
Solution :
A: blood result says positive about the disease \[{{B}_{1}}:\]Person suffers from the disease\[\therefore P({{B}_{1}})=\frac{1}{100}\] \[{{B}_{2}}:\] person does not suffer\[\therefore P({{B}_{2}})=\frac{99}{100}\] \[P(A/{{B}_{1}})=\frac{99}{100},\,\,P(A/{{B}_{2}})=\frac{1}{100}\] \[P({{B}_{1}}/A)=\frac{P({{B}_{1}})P(A/{{B}_{1}})}{P({{B}_{1}}).P(A/{{B}_{1}})+P({{B}_{2}}).P(A/{{B}_{2}})}\] \[=\frac{\frac{1}{100}\cdot \frac{99}{100}}{\frac{1}{100}\cdot \frac{99}{100}+\frac{99}{100}\cdot \frac{1}{100}}=\frac{99}{2\cdot 99}=\frac{1}{2}=50%\]You need to login to perform this action.
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