A) \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]
B) \[{{(N{{H}_{4}})}_{2}}[TiC{{l}_{6}}]\]
C) \[CoS{{O}_{4}}\]
D) \[{{K}_{3}}[Cu{{(CN)}_{4}}]\]
Correct Answer: C
Solution :
In \[{{(N{{H}_{4}})}_{2}}[(TiC{{l}_{6}})],\] \[T{{i}^{4+}}(3{{d}^{0}}\,\,4{{s}^{0}})\] has no unpaired electrons. In \[{{K}_{2}}C{{r}_{2}}{{O}_{7}},C{{r}^{6+}}\] \[(3{{p}^{6}}{{d}^{0}})\] has no unpaired electrons. In \[CoS{{O}_{4}},\,C{{o}^{2+}}({{d}^{7}})\] has unpaired electrons in d-orbitals, so it is both paramagnetic and coloured. In \[{{K}_{3}}[Cu{{(CN)}_{4}}],C{{u}^{+}}(3{{d}^{10}}),\] has no unpaired
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