A) \[-N{{O}_{2}}\] group
B) aromatic \[-N{{H}_{2}}\] group
C) \[-CON{{H}_{2}}\] group
D) aliphatic \[-N{{H}_{2}}\] group
Correct Answer: B
Solution :
\[{{C}_{6}}{{H}_{5}}N{{H}_{2}}+NaN{{O}_{2}}+HCl\xrightarrow[{{0}^{o}}C]{}{{C}_{6}}{{H}_{5}}N=NCl\]You need to login to perform this action.
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