JEE Main & Advanced Sample Paper JEE Main Sample Paper-38

  • question_answer 28) A reaction rate constant is given by \[K=1.2\times {{10}^{10}}{{e}^{-2500/RT}}.\]It means                  

    A)  log K vs T will give a straight line                      

    B)  log K vs 1/T gives a straight line with a slope \[-2500/2.303\text{ }R\]                                     

    C)  half life of reaction will be more at higher temperature

    D)  log K vs 1 /T gives a straight line with a slope 2500/R

    Correct Answer: B

    Solution :

     log\[\log K=\log A-\frac{{{E}_{a}}}{2.303R}\frac{1}{T}\] (Arrhenius equation) Plot of log K Vs 1/T gives a straight line with slope \[-{{E}_{a}}/2.303R\]

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