JEE Main & Advanced Sample Paper JEE Main Sample Paper-38

  • question_answer A non-conducting partition divides a container into two equal compartments. One is filled with helium gas at 200 K and the other is filled with oxygen gas at 400 K. The number of molecules in each gas is the same. If the partition is removed to allow the gases to mix, the final temperature will be

    A)  \[350\,K~\]                  

    B) \[325\,K~\]

    C)  \[300\,K~\]                  

    D)  \[275\,K~\]

    Correct Answer: C

    Solution :

     Here the number of molecules is same. Hence,\[{{T}_{final}}=\frac{{{T}_{1}}+{{T}_{2}}}{2}=\frac{200+400}{2}=300K\]     


You need to login to perform this action.
You will be redirected in 3 sec spinner