A) \[\frac{49}{4}\]
B) \[4\]
C) \[3\]
D) \[12\]
Correct Answer: A
Solution :
\[{{4}^{2}}+4p+12=0\Rightarrow p=-7\] The equation \[{{x}^{2}}+px+q=0\] has equal roots then\[D=0\],or\[{{p}^{2}}=4q\Rightarrow q=\frac{49}{4}\]You need to login to perform this action.
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