A) \[R\]
B) \[R-\{0\}\]
C) \[R-\{1\}\]
D) \[R-\{0,\,\,1\}\]
Correct Answer: C
Solution :
Since \[|x|\] is not diff. at\[x=0\] \[\Rightarrow \]\[|x-1|\]is not diff at\[x=1\].\[{{x}^{n}}|x|\]in\[n\]times diff. at\[x=0\] \[\Rightarrow \]\[{{(x-1)}^{2}}|x-1|\]is twice diff. at\[x=1\]but not thrice diff. at\[x=1\]You need to login to perform this action.
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