A) has value\[0\]
B) has value\[1\]
C) has value\[-\infty \]
D) has value\[\infty \]
Correct Answer: B
Solution :
As\[x\to \frac{1}{3};\,\,\{x+1\}\to \{1+1/3\}\to 1/3\] Similarly\[\{x+2\}\to \frac{1}{3}\]as\[x\to \frac{1}{3}\]\[\Rightarrow \]\[\underset{x\to 1/3}{\mathop{\lim }}\,f(x)=\underset{x\to 1/3}{\mathop{\lim }}\,\frac{x-1/3}{x-1/3}=1\]You need to login to perform this action.
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