A) \[x+\alpha \]
B) \[2x+\alpha \]
C) \[\frac{x}{2}+\alpha \]
D) \[{{x}^{2}}+\alpha \]
Correct Answer: C
Solution :
Differentiating w.r.t\[.x,\] we get \[\frac{1}{f(x)}=\frac{1}{{{(f(x))}^{2}}}2f(x)f'(x)\] \[\Rightarrow \]\[f'(x)=\frac{1}{2}\Rightarrow f(x)=\frac{1}{2}x+C\]where \[C\] is a constant.You need to login to perform this action.
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