A) \[\left( \frac{7}{2},\,\,\frac{1}{2} \right)\]
B) \[\left( \frac{7}{2},\,\,\frac{1}{4} \right)\]
C) \[(1,\,\,4)\]
D) \[(4,\,\,1)\]
Correct Answer: B
Solution :
Let the point be\[({{x}_{1}},\,\,{{y}_{1}})\]. Therefore\[={{({{x}_{1}}-3)}^{2}}\] ... (i) \[\therefore \]Now slope of the tangent at \[({{x}_{1}},\,\,{{y}_{1}})\] is \[2({{x}_{1}}-3),\] but it is equal to \[1\]. Therefore,\[2({{x}_{1}}-3)=1\Rightarrow {{x}_{1}}=\frac{7}{2}\] \[{{y}_{1}}={{\left( \frac{7}{2}-3 \right)}^{2}}=\frac{1}{4}\]. Hence the point is\[\left( \frac{7}{2},\,\,\frac{1}{4} \right)\].You need to login to perform this action.
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