• # question_answer If one root of the equation ${{x}^{2}}+px+12=0$ is $4$ while the equation ${{x}^{2}}+px+q=0$ has equal roots, the value of $q$ is A) $\frac{49}{4}$                                  B) $4$C) $3$                             D) $12$

${{4}^{2}}+4p+12=0\Rightarrow p=-7$ The equation ${{x}^{2}}+px+q=0$ has equal roots then$D=0$,or${{p}^{2}}=4q\Rightarrow q=\frac{49}{4}$