JEE Main & Advanced Sample Paper JEE Main Sample Paper-38

  • question_answer If one root of the equation \[{{x}^{2}}+px+12=0\] is \[4\] while the equation \[{{x}^{2}}+px+q=0\] has equal roots, the value of \[q\] is

    A) \[\frac{49}{4}\]                                  

    B) \[4\]

    C) \[3\]                             

    D) \[12\]

    Correct Answer: A

    Solution :

    \[{{4}^{2}}+4p+12=0\Rightarrow p=-7\] The equation \[{{x}^{2}}+px+q=0\] has equal roots then\[D=0\],or\[{{p}^{2}}=4q\Rightarrow q=\frac{49}{4}\]

adversite


You need to login to perform this action.
You will be redirected in 3 sec spinner

Free
Videos