A) The oxidation state of oxygen is \[+2\] in \[O{{F}_{2}}\].
B) Acidic character follows the order \[{{H}_{2}}O<{{H}_{2}}S<{{H}_{2}}Se<{{H}_{2}}Te\].
C) The tendency to form multiple bonds increases in moving down the group from sulphur to tellurium (towards C and N)
D) Sulphur has a strong tendency to catenae while oxygen shows this tendency to a limited extent.
Correct Answer: C
Solution :
Multiple bonds formation tendency with carbon and nitrogen decreases from sulphur to tellurium. \[C{{S}_{2}}(S=C=S)\] is moderately stable,\[CS{{e}_{2}}(Se=C=Se)\] decomposes readily whereas,\[CT{{e}_{2}}(Te=C=Te)\] does not existYou need to login to perform this action.
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