2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-38

  • question_answer
    If the solution of the linear equations\[x-2y+z=0\]; \[2x-y+3z=0\] and\[\lambda x+y-z=0\] trivial then the value of \[\lambda \] is given by

    A) \[\lambda =-\frac{4}{5}\]                 

    B) \[\lambda \ne -\frac{4}{5}\]

    C) \[\lambda =2\]            

    D) \[\lambda \ne 2\]

    Correct Answer: B

    Solution :

     For trivial solution,\[\left| \begin{matrix}    1 & -2 & 1  \\    2 & -1 & 3  \\    \lambda  & 1 & -1  \\ \end{matrix} \right|\ne 0\Rightarrow -5\lambda -4\ne 0\]or\[\lambda \ne -\frac{4}{5}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner