A) \[\{1\}\]
B) \[\{-2,\,\,1\}\]
C) \[\{1/2,\,\,1,\,\,2\}\]
D) \[\{1/2,\,\,1\}\]
Correct Answer: C
Solution :
\[f(x)=\frac{1}{x-1}\]is discontinuous at\[x=1\]. \[(gof)(x)=g(f(x))=\frac{{{(x-1)}^{2}}}{(2x-1),\,\,(x-2)},\]which is not defined at\[x=1/2,\,\,2\].. Hence the set of points where \[(gof)(x)\] is discontinuous is\[\{1/2,\,\,1,\,\,2\}\]You need to login to perform this action.
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