JEE Main & Advanced Sample Paper JEE Main Sample Paper-38

  • question_answer 78) The set of points where \[f(x)={{(x-1)}^{2}}(x+|x-1|)\] is thrice differentiable, is

    A) \[R\]                            

    B) \[R-\{0\}\]

    C) \[R-\{1\}\]                   

    D) \[R-\{0,\,\,1\}\]

    Correct Answer: C

    Solution :

     Since \[|x|\] is not diff. at\[x=0\] \[\Rightarrow \]\[|x-1|\]is not diff at\[x=1\].\[{{x}^{n}}|x|\]in\[n\]times diff. at\[x=0\] \[\Rightarrow \]\[{{(x-1)}^{2}}|x-1|\]is twice diff. at\[x=1\]but not thrice diff. at\[x=1\]

adversite



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